mirror of https://github.com/n-hys/bash.git
47 lines
1.4 KiB
C
47 lines
1.4 KiB
C
/* strcasestr.c - Find if one string appears as a substring of another string,
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without regard to case. */
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/* Copyright (C) 2000 Free Software Foundation, Inc.
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This file is part of GNU Bash, the Bourne Again SHell.
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Bash is free software: you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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Bash is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with Bash. If not, see <http://www.gnu.org/licenses/>.
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*/
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#include <config.h>
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#include <bashansi.h>
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#include <chartypes.h>
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#include <stdc.h>
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/* Determine if s2 occurs in s1. If so, return a pointer to the
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match in s1. The compare is case insensitive. This is a
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case-insensitive strstr(3). */
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char *
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strcasestr (s1, s2)
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const char *s1;
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const char *s2;
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{
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register int i, l, len, c;
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c = TOLOWER ((unsigned char)s2[0]);
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len = strlen (s1);
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l = strlen (s2);
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for (i = 0; (len - i) >= l; i++)
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if ((TOLOWER ((unsigned char)s1[i]) == c) && (strncasecmp (s1 + i, s2, l) == 0))
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return ((char *)s1 + i);
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return ((char *)0);
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}
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