[MS ABI] Let arbitrary entities participate in vftable ordering

In the Microsoft ABI, the vftable is laid out in the order in the
declaration order of the entities defined within it.

Obviously, only virtual methods end up in the vftable but they will be
placed into the table at the same position as the first entity with the
same name.

llvm-svn: 253523
This commit is contained in:
David Majnemer 2015-11-19 00:03:54 +00:00
parent 905c41b00d
commit 70effde0af
2 changed files with 25 additions and 6 deletions

View File

@ -2882,22 +2882,26 @@ static void GroupNewVirtualOverloads(
// Put the virtual methods into VirtualMethods in the proper order:
// 1) Group overloads by declaration name. New groups are added to the
// vftable in the order of their first declarations in this class
// (including overrides and non-virtual methods).
// (including overrides, non-virtual methods and any other named decl that
// might be nested within the class).
// 2) In each group, new overloads appear in the reverse order of declaration.
typedef SmallVector<const CXXMethodDecl *, 1> MethodGroup;
SmallVector<MethodGroup, 10> Groups;
typedef llvm::DenseMap<DeclarationName, unsigned> VisitedGroupIndicesTy;
VisitedGroupIndicesTy VisitedGroupIndices;
for (const auto *MD : RD->methods()) {
MD = MD->getCanonicalDecl();
for (const auto *D : RD->decls()) {
const auto *ND = dyn_cast<NamedDecl>(D);
if (!ND)
continue;
VisitedGroupIndicesTy::iterator J;
bool Inserted;
std::tie(J, Inserted) = VisitedGroupIndices.insert(
std::make_pair(MD->getDeclName(), Groups.size()));
std::make_pair(ND->getDeclName(), Groups.size()));
if (Inserted)
Groups.push_back(MethodGroup());
if (MD->isVirtual())
Groups[J->second].push_back(MD);
if (const auto *MD = dyn_cast<CXXMethodDecl>(ND))
if (MD->isVirtual())
Groups[J->second].push_back(MD->getCanonicalDecl());
}
for (const MethodGroup &Group : Groups)

View File

@ -299,3 +299,18 @@ struct S {
};
S::S() {}
struct T {
struct U {};
};
struct V : T {
// CHECK-LABEL: VFTable for 'V' (2 entries).
// CHECK-NEXT: 0 | void V::U()
// CHECK-NEXT: 1 | void V::f()
using T::U;
virtual void f();
virtual void U();
V();
};
V::V() {}