Give CanQual<T> an implicit conversion to bool, so that it can be used

in "if" statements like:

  if (CanQual<ReferenceType> RefType = T.getAs<ReferenceType>())

Thanks to Clang for pointing out this mistake :)

llvm-svn: 86995

clang/include/clang/AST/CanonicalType.h

@@ -71,6 +71,9 @@ public:
   /// \brief Implicit conversion to a qualified type.
   operator QualType() const { return Stored; }
 
+  /// \brief Implicit conversion to bool.
+  operator bool() const { return !isNull(); }
+  
   bool isNull() const {
     return Stored.isNull();
   }

clang/lib/Sema/SemaDeclCXX.cpp

@@ -4014,7 +4014,7 @@ bool Sema::CheckOverloadedOperatorDeclaration(FunctionDecl *FnDecl) {
     if (!ResultTy->isDependentType() && ResultTy != Context.VoidPtrTy)
       return Diag(FnDecl->getLocation(),
                   diag::err_operator_new_result_type) << FnDecl->getDeclName()
-                  << Context.VoidPtrTy;
+                  << static_cast<QualType>(Context.VoidPtrTy);
     return ret;
   }