[Sema] Transform the default arguments of a lambda expression when the

lambda expression is instantiated.

Rather than waiting until Sema::CheckCXXDefaultArgExpr tries to
transform the default arguments (which fails because it can't get the
template arguments that are used), transform the default arguments
earlier when the lambda expression is transformed in
TransformLambdaExpr.

rdar://problem/27535319

Differential Revision: https://reviews.llvm.org/D23096

llvm-svn: 289990
This commit is contained in:
Akira Hatanaka 2016-12-16 21:16:57 +00:00
parent 193ee2db47
commit 40281846a1
2 changed files with 31 additions and 1 deletions

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@ -10356,6 +10356,18 @@ TreeTransform<Derived>::TransformLambdaExpr(LambdaExpr *E) {
LSI->CallOperator = NewCallOperator;
for (unsigned I = 0, NumParams = NewCallOperator->getNumParams();
I != NumParams; ++I) {
auto *P = NewCallOperator->getParamDecl(I);
if (P->hasUninstantiatedDefaultArg()) {
EnterExpressionEvaluationContext Eval(
getSema(), Sema::PotentiallyEvaluatedIfUsed, P);
ExprResult R = getDerived().TransformExpr(
E->getCallOperator()->getParamDecl(I)->getDefaultArg());
P->setDefaultArg(R.get());
}
}
getDerived().transformAttrs(E->getCallOperator(), NewCallOperator);
getDerived().transformedLocalDecl(E->getCallOperator(), NewCallOperator);

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@ -1,18 +1,36 @@
// RUN: %clang_cc1 -std=c++14 -fsyntax-only -verify %s
// expected-no-diagnostics
template <class> auto fn0 = [] {};
template <typename> void foo0() { fn0<char>(); }
template<typename T> auto fn1 = [](auto a) { return a + T(1); };
template<typename T> auto v1 = [](int a = T(1)) { return a; }();
struct S {
template<class T>
static constexpr T t = [](int f = T(7)){return f;}(); // expected-error{{constexpr variable 't<int>' must be initialized by a constant expression}} expected-error{{a lambda expression may not appear inside of a constant expression}} expected-note{{cannot be used in a constant expression}}
};
template <typename X>
int foo2() {
X a = 0x61;
fn1<char>(a);
(void)v1<int>;
(void)S::t<int>; // expected-note{{in instantiation of static data member 'S::t<int>' requested here}}
return 0;
}
template<class C>
int foo3() {
C::m1(); // expected-error{{type 'long long' cannot be used prior to '::' because it has no members}}
return 1;
}
template<class C>
auto v2 = [](int a = foo3<C>()){}; // expected-note{{in instantiation of function template specialization 'foo3<long long>' requested here}}
int main() {
v2<long long>(); // This line causes foo3<long long> to be instantiated.
v2<long long>(2); // This line does not.
foo2<int>();
}