Get rid of the printout from the low-level system interface
llvm-svn: 15161
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8171b14fcc
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2731ead702
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@ -182,34 +182,23 @@ int llvm::RunProgramWithTimeout(const std::string &ProgramPath,
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alarm(NumSeconds);
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int Status;
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while (wait(&Status) != Child) {
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while (wait(&Status) != Child)
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if (errno == EINTR) {
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if (Timeout) {
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static bool FirstTimeout = true;
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if (FirstTimeout) {
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std::cout <<
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"*** Program execution timed out! This mechanism is designed to handle\n"
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" programs stuck in infinite loops gracefully. The -timeout option\n"
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" can be used to change the timeout threshold or disable it completely\n"
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" (with -timeout=0). This message is only displayed once.\n";
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FirstTimeout = false;
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}
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// Kill the child.
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kill(Child, SIGKILL);
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if (wait(&Status) != Child)
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std::cerr << "Something funny happened waiting for the child!\n";
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alarm(0);
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sigaction(SIGALRM, &Old, 0);
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return -1; // Timeout detected
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} else {
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std::cerr << "Error waiting for child process!\n";
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exit(1);
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}
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// Kill the child.
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kill(Child, SIGKILL);
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if (wait(&Status) != Child)
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std::cerr << "Something funny happened waiting for the child!\n";
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alarm(0);
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sigaction(SIGALRM, &Old, 0);
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return -1; // Timeout detected
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} else {
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std::cerr << "Error waiting for child process!\n";
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exit(1);
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}
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}
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alarm(0);
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sigaction(SIGALRM, &Old, 0);
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