E0716: clarify that equivalent code example is erroneous

In E0716, there is a code block that is equivalent to the erroneous
code example. Especially when viewed with `rustc --explain`, it's
not obvious that it is also erroneous, and some users have been
confused when they try to change their code to match the erroneous
equivalent.
This commit is contained in:
Taylor Yu 2021-06-19 15:28:32 -05:00
parent e062e5d34e
commit 92197a551f
1 changed files with 4 additions and 2 deletions

View File

@ -14,14 +14,16 @@ Here, the expression `&foo()` is borrowing the expression `foo()`. As `foo()` is
a call to a function, and not the name of a variable, this creates a
**temporary** -- that temporary stores the return value from `foo()` so that it
can be borrowed. You could imagine that `let p = bar(&foo());` is equivalent to
this:
the following, which uses an explicit temporary variable.
Erroneous code example:
```compile_fail,E0597
# fn foo() -> i32 { 22 }
# fn bar(x: &i32) -> &i32 { x }
let p = {
let tmp = foo(); // the temporary
bar(&tmp)
bar(&tmp) // error: `tmp` does not live long enough
}; // <-- tmp is freed as we exit this block
let q = p;
```